Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 394: 116

Answer

$\dfrac{(x-9)}{(2x-1)}$

Work Step by Step

Given: $\dfrac{x^2-7x-18}{2x^2+3x-2}$ This can be factorize as: $\dfrac{x^2-7x-18}{2x^2+3x-2}=\dfrac{x^2-9x+2x-18}{2x^2+4x-x-2}$ or, $=\dfrac{(x+2)(x-9)}{(x+2)(2x-1)}$ Hence, $=\dfrac{(x-9)}{(2x-1)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions
GradeSaver will pay $500 for your Textbook Answer contributions