Answer
Does not make sense.
Work Step by Step
A quadratic equation can be represented as $px^2+qx+r=0$; where $p,q,r$ are real numbers and $p$ cannot be equal to zero, that is , $p \neq 0$ and the roots /solutions of a quadratic equation corresponds to the $x$-intercepts of the graph which can be only $1$.
Hence, the given statement does not make sense.
