Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 394: 111

{$-2,\dfrac{10}{3}$}

Since, $|3x-2|=8$ Apply the definition of Absolute value. We have $3x-2=8$ and $3x-2=-8$ This implies that $3x=10$ and $3x=-6$ Thus, $x=\dfrac{10}{3}$ and $x=-2$ Solution set is $x=${$-2,\dfrac{10}{3}$}