Answer
$x=-4$; $x=1$;
Work Step by Step
We use a graphing calculator to graph the function $y=x^2+3x-4$.
From the graph we notice that the $x$-intercepts are:
$$\begin{align*}
x_1&=-4\\
x_2&=1.
\end{align*}$$
We check if the values $x_1$ and $x_2$ work for the equation $x^2+3x-4=0$:
$$\begin{align*}
x_1&=-4\\
(-4)^2+3(-4)-4&\stackrel{?}{=}0\\
16-12-4&\stackrel{?}{=}0\\
0&=0\checkmark\\\\
x_2&=1\\
1^2+3(1)-4&\stackrel{?}{=}0\\
1+3-4&\stackrel{?}{=}0\\
0&=0\checkmark
\end{align*}$$
Therefore the solutions of the equation are $-4$ and $1$.
