Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.6 - A General Factoring Strategy - Exercise Set - Page 378: 9

Answer

$2b(a-3)(2a+5)$

Work Step by Step

Consider the polynomial $(4a^2b-2ab-30b)$ Take out common terms. or, $=2b(2a^2-a-15)$ Apply rule of factorization. $=2b(2a^2-6a+5a-15)$ $=2b[2a(a-3)+5(a-3)]$ Hence, $(4a^2b-2ab-30b)=2b(a-3)(2a+5)$
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