Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.6 - A General Factoring Strategy - Exercise Set - Page 378: 5

Answer

$3(3x-1)(9x^2+3x+1)$

Work Step by Step

Consider the polynomial $(81x^3-x)$ Take out common term, that is, $3$. $\implies 3(27x^3-1)$ or, $=3[(3x)^3-1]$ Apply difference of cubes formula. $=3(3x-1)(9x^2+3x+1)$ Hence, $(81x^3-x)=3(3x-1)(9x^2+3x+1)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions
GradeSaver will pay $500 for your Textbook Answer contributions