Answer
$(x+4)(x-4)(y-2)$
Work Step by Step
Consider the polynomial $(x^2y-16y+32-2x^2)$
$\implies (x^2y-2x^2)-(16y-32)$
Take out common terms.
or, $=x^2(y-2)-16(y-2)$
$=(x^2-16)(y-2)$
Apply difference of squares formula.
$=(x^2-4^2)(y-2)$
Hence, $(x^2y-16y+32-2x^2)=(x+4)(x-4)(y-2)$
