Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.6 - A General Factoring Strategy - Exercise Set - Page 378: 3



Work Step by Step

Consider the polynomial $3x^2+18x+27$ Take out common term, that is, $3$. $\implies 3(x^2+6x+9)$ or, $=3(x^2+6x+3^2)$ or,$=3(x+3)(x+3)$ Hence, $3x^2+18x+27=3(x+3)^2$
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