# Chapter 5 - Section 5.6 - A General Factoring Strategy - Exercise Set - Page 378: 13

$11x(x^2+y)(x^2-y)$

#### Work Step by Step

The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$. The square of a binomial sum is: $(A+B)^2=A^2+2AB+B^2$. The square of a binomial difference is: $(A-B)^2=A^2-2AB+B^2$. Hence here: $11x^5-11xy^2=\\=11x(x^4-y^2)\\=11x((x^2)^2-y^2)\\=11x(x^2+y)(x^2-y)$

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