## Intermediate Algebra for College Students (7th Edition)

$x(6-x)(36+6x+x^2)$
Factor out $x$ to obtain: $=x(216-x^3) \\=x(6^3-x^3)$ This binomial is a difference of two cubes. RECALL: $a^3-b^3=(a-b)(a^2+ab+b^2)$ Factor the difference of two cubes using the formula above with $a=6$ and $b=x$ to obtain: $=x(6-x)(6^2+6(x) + x^2) \\=x(6-x)(36+6x+x^2)$