Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 372: 57



Work Step by Step

RECALL: $a^2-2ab+b^2=(a-b)^2$ The given trinomial can be written as: $=(8y)^2-2(8y)(1) + 1^2$ This trinomial is in the same form as the perfect square trinomial above, where $a=8y$ and $b=1$. Factor the perfect square trinomial using the formula above to obtain: $=(8y-1)^2$
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