Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set: 84

Answer

$(xy+4)(x^2y^2-4xy+16)$

Work Step by Step

The given binomial can be written as: $=(xy)^3+4^3$ This binomial is a sum of two cubes. RECALL: $a^3+b^3=(a+b)(a^2-ab+b^2)$ Factor the difference of two cubes using the formula above with $a=xy$ and $b=4$ to obtain: $=(xy+4)[(xy)^2-xy(4)+4^{2}] \\=(xy+4)(x^2y^2-4xy+16)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.