Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 372: 46

Answer

$(x+3)^2(x-3)$

Work Step by Step

The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$. Hence here: $x^3+3x^2-9x-27=x^2(x+3)-9(x+3)=(x+3)(x^2-9)=(x+3)(x^2-3^2)=(x+3)(x+3)(x-3)=(x+3)^2(x-3)$
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