Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set: 39

Answer

$(x-2)(x+2)(x^2+4)$

Work Step by Step

The given binomial can be written as: $=(x^2)^2-4^2$ The binomial is a difference of two squares. RECALL: $a^2-b^2=(a-b)(a+b)$ Factor the difference of two square using the formula above with $a=x^2$ and $b=4$ to obtain: $=(x^2-4)(x^2+4) \\=(x^2-2^2)(x^2+4)$ The first factor is a difference of two squares. Factor using the formula above with $a=x$ and $b=2$ to obtain: $=(x-2)(x+2)(x^2+4)$
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