Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 206: 35

Answer

$x=80,y=50$

Work Step by Step

As per the statement: $x+2y=180$ and $y+2x-30=180$ Plug $x=180-2y$ in the second equation, then we get $y+2(180-2y)-30=180 \implies -3y=-150$ or, $y=50$ Now, $x+2(50)=180 \implies x=80$ Thus, $x=80,y=50$
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