Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 206: 24

$x=6,y=4$

As per the statement: $x+y=10$ and $2.00x+3.25y=(2.50)(10)$ After plugging the variable $x$ form the first equation in the second equation, we get $2.00(10-y)+3.25y=(2.50)(10) \implies 1.25y=5$ or, $y=4$ Now, $x+4=10 \implies x=6$ Thus, $x=6,y=4$