Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 206: 25



Work Step by Step

As per the statement: $x+y=15$ and $0.05x+0.10y=1.10$ After plugging the variable $x$ form the first equation in the second equation, we get $0.05(15-y)+0.10y=1.10 \implies 0.05y=0.35$ or, $y=7$ Now, $x+7=15 \implies x=8$ Thus, $x=8,y=7$
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