Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 206: 27



Work Step by Step

As per the statement: $x+y=800/5$ and $x-y=800/8$ After adding the given two equations, we get $2x=160+100 \implies 2x=260$ or, $x=130$ Now, $130+y=800/5 \implies y=30$ Thus, $x=130,y=30$
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