## Intermediate Algebra for College Students (7th Edition)

$x=92,y=84$
As per the statement: $x-y=8$ and $\dfrac{x+y}{2}=88$ Plug $x=8+y$ in the second equation, then we get $\dfrac{8+y+y}{2}=88 \implies 2y=168$ or, $y=84$ Now, $x-84=8 \implies x=92$ Thus, $x=92,y=84$