Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 206: 34



Work Step by Step

As per the statement: $x-y=8$ and $\dfrac{x+y}{2}=88$ Plug $x=8+y$ in the second equation, then we get $\dfrac{8+y+y}{2}=88 \implies 2y=168$ or, $y=84$ Now, $x-84=8 \implies x=92$ Thus, $x=92,y=84$
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