Answer
$(x,y)=(-4,2)$; a unique solution
Work Step by Step
Since, we have two equations $3x+2y=-8$ and $2x+5y=2$, we have
From the given two equations, we have $y=-(\dfrac{8+3x}{2})$
Plug the value of y in $2x+5y=2$,then
$4x-15x=4+40$
or, $-11x=44$
or, $x=-4$
Now, $y=-(\dfrac{8+3x}{2})=-(\dfrac{8+3(-4)}{2})=2$
Thus, $(x,y)=(-4,2)$; a unique solution