Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Review Exercises - Page 248: 1

Answer

$(4,2)$ is not a solution

Work Step by Step

Need to proof whether $(4,2)$ is a solution of the given equations. From the given two equations $2x-5y=-2$ and $3x+4y=4$, we have $x=\dfrac{5y-2}{2}$ Let us plug the above value in equation $3x+4y=4$, we have $3(\dfrac{5y-2}{2})+4y=4$ or, $15y+8y=8+6$ or, $23y=14$ or, $y=\dfrac{14}{23}$ Thus, $(4,2)$ is not a solution of the given two equations.
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