Answer
$(4,2)$ is not a solution
Work Step by Step
Need to proof whether $(4,2)$ is a solution of the given equations.
From the given two equations $2x-5y=-2$ and $3x+4y=4$, we have $x=\dfrac{5y-2}{2}$
Let us plug the above value in equation $3x+4y=4$, we have
$3(\dfrac{5y-2}{2})+4y=4$
or, $15y+8y=8+6$
or, $23y=14$
or, $y=\dfrac{14}{23}$
Thus, $(4,2)$ is not a solution of the given two equations.