Answer
No solution
Work Step by Step
Since, we have two equations $x-2y+3=0$ and $2x-4y+7=0$
From the given two equations, we have $x=2y-3$
Plug the value of $x$ in $2x-4y+7=0$, we have
$2(2y-3)-4y+7=0$
or, $1=0$
which cannot be true solution.
Thus, No solution
