## Intermediate Algebra for College Students (7th Edition)

$(x,y)=(3,4)$; a unique solution
Since, we have two equations $2x-y=2$ and $x+2y=11$, we have From the given two equations, we have $y=2x-2$ Plug the value of y in $2x-y=2$ ,then $2x-(2x-2)=2$ or, $x+4x=11+4$ or, $5x=15$ or, $x=3$ Now, $y=2x-2=2(3)-2=4$ Thus, $(x,y)=(3,4)$; a unique solution