Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Review Exercises - Page 248: 3

Answer

$\{(2,3)\}$.

Work Step by Step

First equation $x+y=5$. Plug $y=0$ into the equation. $\Rightarrow x+(0)=5$ $\Rightarrow x=5$ $x−$ intercept is $A=(5,0)$. Plug $x=0$ into the equation. $\Rightarrow (0)+y=5$ $\Rightarrow y=5$ $y−$ intercept $B=(0,5)$. Second equation $3x-y=3$. Plug $y=0$ into the equation. $\Rightarrow 3x-(0)=3$ $\Rightarrow 3x=3$ $\Rightarrow \frac{3x}{3}=\frac{3}{3}$ $\Rightarrow x=1$ $x−$ intercept $C=(1,0)$. Plug $x=0$ into the equation. $\Rightarrow 3(0)-y=3$ $\Rightarrow -y=3$ $\Rightarrow -y(-1)=3(-1)$ $\Rightarrow y=-3$ $y−$ intercept $D=(0,-3)$. Draw two lines using intercept points. The intersection point is $E=(2,3)$. Hence, the solution set is $=\{(2,3)\}$.
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