Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Review Exercises - Page 248: 15

Answer

$\$2500$ at $4\%$. $\$6500$ at $7\%$.

Work Step by Step

Step 1: Assume unknown quantities as variables. Let the first fund at $4\%$ interest be $=x$. Let the second fund at $7\%$ interest be $=y$. Step 2: Write the system of equations. $4\%$ of the first fund is $0.04x$. $7\%$ of the second fund is $0.07y$. The given values are Total fund $= \$9000$ Total interest earned $=\$555$. Or we can write. $\Rightarrow x+y=9000$ ...... (1) $\Rightarrow 0.04x+0.07y=555$ ...... (2) Step 3: Solve the system of equations. Multiply equation (1) by $-0.04$. $\Rightarrow -0.04x-0.04y=-360$ ...... (3) Add equation (2) and (3). $\Rightarrow 0.04x+0.07y-0.04x-0.04y=555-360$ Simplify. $\Rightarrow 0.03y=195$ Divide both sides by $0.03$. $\Rightarrow \frac{0.03y}{0.03}=\frac{195}{0.03}$ Simplify. $\Rightarrow y=6500$ Plug the value of $y$ into equation (1). $\Rightarrow x+6500=9000$ Isolate $x$. $\Rightarrow x=9000-6500$ Simplify. $\Rightarrow x=2500$. Step 4: Check the answers. Substitute the values of $x$ and $y$ into equation (1). $\Rightarrow 6500+2500=9000$ $\Rightarrow 9000=9000$ True.
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