## Intermediate Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 11 - Section 11.3 - Geometric Sequences and Series - Exercise Set: 6

#### Answer

$r= \dfrac{2}{3}$

#### Work Step by Step

The common ratio $r$ can be found by dividing a term by the previous term. Thus, the common ratio of the given sequence is: $\require{cancel} r=\dfrac{\frac{8}{3}}{4} \\r= \dfrac{8}{3(4)} \\r= \dfrac{\cancel{8}2}{3\cancel{(4)}} \\r= \dfrac{2}{3}$

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