## Intermediate Algebra for College Students (7th Edition)

$\dfrac{529}{999}$
Sum of the first $n$ terms terms of a geometric sequence can be calculated as: $s_n=\dfrac{a_1}{(1-r)}$ $r$ refers to common ratio and $r=\dfrac{1}{1000}=0.01$ and $S_n=0.\overline{529}$ Apply the formula. $s_n=\dfrac{0.529}{(1-0.001)}=\dfrac{0529}{0.999}=\dfrac{529}{999}$