Intermediate Algebra for College Students (7th Edition)

Published by Pearson

Chapter 11 - Section 11.3 - Geometric Sequences and Series - Exercise Set - Page 854: 19

Answer

$a_{12}=-10,240$

Work Step by Step

RECALL: The $n^{th}$ term ($a_n$) of a geometric sequence can be found using the formula: $a_n= a_1 \cdot r^{n-1}$ where $a_1$ = first term r = common ratio Use the formula above and the give values of the first term and the common ratio to obtain: $a_n=5 \cdot (-2)^{n-1} \\a_{12}=5 \cdot (-2)^{12-1} \\a_{12}=5 \cdot (-2)^{11} \\a_{12}=5 \cdot (-2048) \\a_{12}=-10,240$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.