Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.3 - Geometric Sequences and Series - Exercise Set - Page 854: 5

Answer

$r= \dfrac{3}{2}$

Work Step by Step

The common ratio $r$ can be found by dividing a term by the previous term. Thus, the common ratio of the given sequence is: $r=\dfrac{\frac{9}{2}}{3} \\r= \dfrac{9}{2(3)} \\r=\dfrac{9}{6} \\r= \dfrac{3}{2}$
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