Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.3 - Geometric Sequences and Series - Exercise Set - Page 854: 22

Answer

$-250$

Work Step by Step

The nth term can be obtained by $a_n=a_1\cdot r^{n-1}$ where $a_1$ is the first term and $r$ is the common ratio. Hence here: $a_6=8000\cdot(\frac{-1}{2})^5=8000\cdot\frac{-1}{32}=-250$
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