Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.3 - Geometric Sequences and Series - Exercise Set: 12

Answer

$a_1=24 \\a_2=8 \\a_3=\frac{8}{3} \\a_4=\frac{8}{9} \\a_5=\frac{8}{27}$

Work Step by Step

Multiply the common ratio to get the next term to obtain: $a_1=24 \\a_2=24(\frac{1}{3}) = 8 \\a_3=8(\frac{1}{3})=\frac{8}{3} \\a_4=\frac{8}{3}(\frac{1}{3})=\frac{8}{9} \\a_5=\frac{8}{9}(\frac{1}{3}) = \frac{8}{27}$
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