Answer
$1727$
Work Step by Step
Here, $a_1=5, d=7$
Sum of $22$nd term of an arithmetic sequence can be calculated as:
$S_n=\dfrac{n}{2}[2a_1+(n-1)d]$
Now,
$S_{22}=\dfrac{22}{2}[2(5)+(22-1)7]=11[10+(21)7]=1727$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Review Exercises - Page 869: 19
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