Answer
$15150$
Work Step by Step
Here, $a_1=3, d=3$
Sum of first $100$th term of an arithmetic sequence can be calculated as:
$S_n=\dfrac{n}{2}[2a_1+(n-1)d]$
Now,
$S_{100}=\dfrac{100}{2}[2(3)+(100-1)3]=50[6+(99)3]=15150$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Review Exercises - Page 869: 21
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