Work Step by Step
Need to find the first four terms of $a_n=7n+4$ when $n=1,2,3,4$ Thus, $a_1=7(1)+4=11$ ; $a_2=7(2)+4=18$; $a_3=7(3)+4=25$ ; $a_4=7(4)+4=32$ Hence, the first four terms are: $11,18,25,32$
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