Answer
$a_1=\dfrac{3}{2}$,$a_2=1$,$a_3=\dfrac{1}{2}$,$a_4=0$,
$a_5=\dfrac{-1}{2}$,$a_6=-1$
Work Step by Step
Initial term, $a_1=\dfrac{3}{2}$ and common ratio $d=\dfrac{-1}{2}$.
Now, we need first six terms such as:
$a_1=\dfrac{3}{2}$,$a_2=\dfrac{3}{2}+(\dfrac{-1}{2})=1$,$a_3=1+(-\dfrac{1}{2})=\dfrac{1}{2}$,$a_4=\dfrac{1}{2}+(-\dfrac{1}{2})=0$,
$a_5=0+(-\dfrac{1}{2})=\dfrac{-1}{2}$,$a_6=\dfrac{-1}{2}+(-\dfrac{1}{2})=-1$
Hence, six terms are: $a_1=\dfrac{3}{2}$,$a_2=1$,$a_3=\dfrac{1}{2}$,$a_4=0$,
$a_5=\dfrac{-1}{2}$,$a_6=-1$
