Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Review Exercises - Page 869: 15


$a_n=-7+(n-1)4$ ; $a_{20}=69$

Work Step by Step

Here, $a_1=-7, d=4$ n-th term an arithmetic series can be calculated as: $a_n=a_1+(n-1)d$ Thus, $a_n=-7+(n-1)4$ Also, $a_{20}=-7+(20-1)(4)=69$
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