Answer
$a_n=200+(n-1)(-20)$ ; $a_{20}=-180$
Work Step by Step
Here, $a_1=200, d=-20$
n-th term an arithmetic series can be calculated as:
$a_n=a_1+(n-1)d$
Thus, $a_n=200+(n-1)(-20)$
Also, $a_{20}=200+(20-1)(-20)=-180$
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