Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set: 61

Answer

$9x^{14}$

Work Step by Step

RECALL: (i) The products-to-powers rule states that: $(ab)^n=a^nb^n$ (ii) The power rule states that $(a^m)^n=a^{mn}$ Use the products-to-powers rule to find: $=(-3)^2(x^7)^2 \\=9(x^7)^2$ Use the power rule to find: $=9x^{7(2)} \\=9x^{14}$
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