## Intermediate Algebra for College Students (7th Edition)

$(-5)^{-2} =\dfrac{1}{(-5)^2}=\dfrac{1}{25}$
RECALL: The negative-exponent rule of exponents states that: $a^{-m} =\dfrac{1}{a^m}$ and $\dfrac{1}{a^{-m}} = a^m$, where $a \ne 0$. Use the negative-exponent rule to find: $(-5)^{-2} =\dfrac{1}{(-5)^2}=\dfrac{1}{25}$