Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set: 49

Answer

$\dfrac{y^5}{x^2}$

Work Step by Step

RECALL: The negative-exponent rule of exponents states that: $a^{-m} = \dfrac{1}{a^m}$ or $\dfrac{1}{a^{-m}} = a^m$ where $a \ne 0$. Use the negative-exponent rule to obtain: $=\dfrac{\frac{1}{x^2}}{\frac{1}{y^5}} \\=\dfrac{1}{x^2} \cdot \dfrac{y^5}{1} \\=\dfrac{y^5}{x^2}$
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