Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set: 50

Answer

$\dfrac{x^{-3}}{y^{-7}} =\dfrac{y^7}{x^3}$

Work Step by Step

RECALL: The negative-exponent rule of exponents states that: $a^{-m} =\dfrac{1}{a^m}$ and $\dfrac{1}{a^{-m}} = a^m$, where $a \ne 0$. Use the negative-exponent rule to find: $\dfrac{x^{-3}}{y^{-7}} =\dfrac{\frac{1}{x^3}}{\frac{1}{y^7}}=\dfrac{1}{x^3} \cdot \dfrac{y^7}{1}=\dfrac{y^7}{x^3}$
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