Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set: 43

Answer

$8x^{-7}y^{3} =\dfrac{8y^3}{x^7}$

Work Step by Step

RECALL: The negative-exponent rule of exponents states that: $a^{-m} =\dfrac{1}{a^m}$ and $\dfrac{1}{a^{-m}} = a^m$, where $a \ne 0$. Use the negative-exponent rule to find: $8x^{-7}y^{3} = 8 \cdot \dfrac{1}{x^7} \cdot y^3 =\dfrac{8y^3}{x^7}$
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