## Intermediate Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set: 52

#### Answer

$\dfrac{a^{-3}b^8}{c^{-2}} =\dfrac{b^8c^2}{a^3}$

#### Work Step by Step

RECALL: The negative-exponent rule of exponents states that: $a^{-m} =\dfrac{1}{a^m}$ and $\dfrac{1}{a^{-m}} = a^m$, where $a \ne 0$. Use the negative-exponent rule to find: $\dfrac{a^{-3}b^8}{c^{-2}} =\dfrac{\frac{b^8}{a^3}}{\frac{1}{c^2}}=\dfrac{b^8}{a^3} \cdot \dfrac{c^2}{1}=\dfrac{b^8c^2}{a^3}$

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