Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises - Page 100: 99

Answer

$-24x^7y^4$

Work Step by Step

RECALL: (i) $a^m \cdot a^n = a^{m+n}$ (ii) $(ab)^{m} = a^mb^m$ (iii) $(a^m)^n=a^{mn}$ Use rule (ii) above to obtain: $=(-3xy^4) (2^3)(x^2)^3 \\=(-3xy^4)(8)(x^2)^3$ Use rule (iii) above to obtain: $=(-3xy^4)(8x^{2(3)}) \\=(-3xy^4)(8x^6)$ Multiply the numerical coefficients, then use rule (ii) above to obtain: $=-24x^{1+6}y^4 \\=-24x^7y^4$
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