Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises - Page 100: 87

Answer

$F=\dfrac{9C+160}{5}$

Work Step by Step

Multiply $9$ on both sides of the equation to obtain: $9C=5F-160$ Add 160 on both sides of the equation to obtain: $9C+160=5F$ Divide $5$ on both sides of the equation to obtain: $\dfrac{9C+160}{5}=F$
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