Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises - Page 100: 111


There are $2.88\times 10^{13}$ red blood cells in the body of a 180-pound person.

Work Step by Step

$180\: pounds \times\frac{ 3.2 \times 10^{4}\:microliters\: of\: blood}{pound} \times \frac{5 \times10^{6}\: red\: blood\: cells}{microliter\: of\: blood}$ Recall the multiplication of scientific notation: $(a \times 10^{n})(b \times 10^{m}) = (a \times b) \times 10^{n+m}$ Thus, the whole equation can be written as: $$180 [ (3.2 \times 10^{4}) \times(5 \times10^{6})]$$ $$=180[(3.2\times5)\times 10^{4+6}]$$ $$=180[16\times 10^{10}]$$ $$=2880\times 10^{10}$$ Since the numerical factor, $a$, should be a number between 1 and 10, then this could be rewritten as: $$2.88\times 10^{13}$$
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