Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises: 110


$2.5 \times 10$

Work Step by Step

Divide the corresponding parts to obtain: $=\dfrac{5}{20} \times \dfrac{10^{-6}}{10^{-8}} \\=0.25 \times 10^{-6-(-8)} \\=0.25 \times 10^{-6+8} \\=0.25 \times 10^2$ Simplify to put the number in scientific notation. $=2.5 \times 10^{2-1} \\=2.5 \times 10^1 \\=2.5 \times 10$
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