Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises: 92

Answer

$\dfrac{x^4y^7}{9}$

Work Step by Step

RECALL: $a^{-m}=\dfrac{1}{a^{m}}, a\ne0$ Use the rule above to obtain: $=\dfrac{\frac{1}{3^2}\cdot x^4}{\frac{1}{y^7}} \\=\dfrac{\frac{1}{9}\cdot x^4}{\frac{1}{y^7}}$ Use the rule $\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \cdot \frac{d}{c}$ to obtain: $=\dfrac{1}{9} \cdot x^4 \cdot \dfrac{y^7}{1} \\=\dfrac{x^4y^7}{9}$
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