Intermediate Algebra for College Students (7th Edition)

Published by Pearson

Chapter 1 - Review Exercises - Page 100: 88

Answer

$g=\dfrac{s-vt}{t^2}$

Work Step by Step

Subtract $vt$ on both sides of the equation: $s-vt=gt^2$ Divide $t^2$ on both sides of the equation to obtain: $\dfrac{s-vt}{t^2}=g$

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