Answer
$\frac{4}{85}+\frac{33i}{85}$
Work Step by Step
$\frac{3+2i}{6-7i}$
=$\frac{3+2i}{6-7i}\times\frac{6+7i}{6+7i}$
=$\frac{(3+2i)(6+7i)}{6^{2}-(7i)^{2}}$
=$\frac{3(6+7i)+2i(6+7i)}{36-49i^{2}}$
=$\frac{18+21i+12i+14i^{2}}{36-49(-1)}$
=$\frac{18+33i-14}{85}$
=$\frac{4+33i}{85}$
=$\frac{4}{85}+\frac{33i}{85}$
